Distance between focus and centre of curvature is equal to .

height of the mirror

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radius of curvature

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half of the radius

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Solution

The correct option is C half of the radius
Focus is the midpoint between the pole and the centre of curvature of a mirror. So, the required distance is half of radius of curvature.

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Similar questions

Q. The real image formed by a concave mirror is smaller than the object if the object is:

(a) between centre of curvature and focus
(b) at a distance greater than radius of curvature
(c) at a distance equal to radius of curvature
(d) at a distance equal to focal length

Q. A concave mirror produces magnification of +4. The object is placed:

(a) at the focus
(b) between focus and centre of curvature
(c) between focus and pole
(d) beyond the centre of curvature

Q. If a concave mirror forms a real magnified image of an object, the object is located

(a) between pole and focus
(b) between focus and centre of curvature
(c) beyond centre of curvature
(d) at centre of curvature

In order to obtain a magnification of, -2 (minus 2) with a concave mirror, the object should be placed : (a) between pole and focus (b) between focus and centre of curvature (c) at the centre of curvature (d) beyond the centre of curvature

Q. What is the relation between focus and centre of curvature

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Distance between focus and centre of curvature is equal to .

The correct option is C half of the radiusFocus is the midpoint between the pole and the centre of curvature of a mirror. So, the required distance is half of radius of curvature.

The correct option is C half of the radius
Focus is the midpoint between the pole and the centre of curvature of a mirror. So, the required distance is half of radius of curvature.