Distance between the following pairs of points in the ascending order is A)(−3,45∘),(7,105∘) B)(√2,π4),(2,π2) C)(3,π6),(7,π6)
A
B, C, A
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B
B, A, C
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C
A, C, B
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D
A, B, C
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Solution
The correct option is A B, C, A Distance between two points is d=√r21+r22−2r1r2cos(θ1−θ2) A) Points are (−3,450),(7,1050) d1=√9+49+42cos(−600) ⇒d1=√79 B)Points are (√2,π4),(2,π2) d2=√2+4−4√2cos(−π4) d2=√2 C) Points are (3,π6),(7,π6) d3=√9+49−42cos(0) d3=4 So, arranging the distances in ascending order d2,d3,d1 or B C A