Question

Distance between the genes a, b, c and d in map units is $a-d=3.5,b-c=1,a-b=6,c-d=1.5$ and $a-c=5$. Find out the sequence of the genes.

• A. a d c b
• B. a c d b
• C. a b c d
• D. a c b d
• E. a d b c

Answer 1

The correct option is A a d c b

Given data

$a-d=35$ map unit

$b-c=1$ map unit

$a-b=6$ map unit

$c-d=1.5$ map unit

$a-c=5$ map unit

All that are located on one geves

So, correct sequence is $adcb$

Hence option $A$ is correct