Distance between two cities $A$ and $B$ is $425$ km. If a car leaves $A$ at $2$ PM and reaches $B$ at $10 : 30$ PM, then what is the speed of the car?

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Solution

We know that

Speed $= \frac{D i s t a n c e}{T i m e}$

Distance $= 425$ km

Time $= 10.5 - 2 = 8.5$ hours

Speed of the car $= \frac{D i s t a n c e}{T i m e}$

$= \frac{425}{8.5}$

$= 50$

$∴$ So, the speed of car is $50$ km/hour.

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Distance between two cities A and B is 425 km. If a car leaves A at 2 PM and reaches B at 10:30 PM, then what is the speed of the car?

We know thatSpeed =DistanceTimeDistance =425kmTime =10.5−2=8.5hoursSpeed of the car =DistanceTime=4258.5=50∴ So, the speed of car is 50 km/hour.

Distance between two cities $A$ and $B$ is $425$ km. If a car leaves $A$ at $2$ PM and reaches $B$ at $10 : 30$ PM, then what is the speed of the car?

We know that

Speed $= \frac{D i s t a n c e}{T i m e}$

Distance $= 425$ km

Time $= 10.5 - 2 = 8.5$ hours

Speed of the car $= \frac{D i s t a n c e}{T i m e}$

$= \frac{425}{8.5}$

$= 50$

$∴$ So, the speed of car is $50$ km/hour.