Distance between two lines respresented by the line pair, x2−4xy+4y2+x−2y−6=0 is
A
1√5
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B
√5
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C
2√5
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D
none of these
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Solution
The correct option is B√5 As h2=4=1×4=ab and bg2=4×(14)=1×(1)=af2 Therefore the lines in x2−4xy+4y2+x−2y−6=0 are parallel and the distance between the two lines =2√g2−ac√a(a+b)=2√14−1×(−6)√1(1+4)=√25√5=√5