Distance between two parallel planes 2x + y + 2z = 8 and 4x + 2y + 4z + 5 = 0 is
32
52
72
92
Given planes are 2x+y+2z−8=0 and 2x+y+2z+52=0∴ Distance between two planes=|c1−c2|√a2+b2+c2=∣∣∣−8−52√22+12+22∣∣∣=2123=72