Distance between two parallel planes 2x+y+2z=8 and 4x+2y+4z+5=0 is
A
92
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B
52
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C
72
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D
32
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Solution
The correct option is C72 Given planes are 2x+y+2z-8=0 or 4x+2y+4z-16=0 ⋯(i) and 4x+2y+4z+5=0 ⋯(ii) Distance between two parallel planes =∣∣∣−16−5√42+22+42∣∣∣=216=72