wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Distance between two successive base pairs in DNA is

A
0.34nm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.34˚A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3.4nm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
34˚A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.34nm
The diameter of the B-DNA is 20 Angstroms, and the distance between base pairs is 3.4 Angstroms or 0.34 nm. The base pairing of opposite strands is stereochemically selective, adenine always pairing with thymine, and guanine with cytosine. Two and three hydrogen bonds are formed in A-T and G-C base pairs, respectively. In Z-DNA which is thinner than B-DNA, average distance per base pair along the DNA axis is 0.38 nm, and in A-DNA which is thicker it is 0.23 nm. So, the correct answer is '0.34nm'.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nucleic Acids
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon