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Question

Distance of the centre of mass of a solid uniform cone from its vertex is $z_{0}$ . If the radius of its base is R and its height is h then $z_{0}$ is equal to :

\frac{3 h}{4}

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\frac{5 h}{8}

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\frac{3 h^{2}}{8 R}

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\frac{h^{2}}{4 R}

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Solution

The correct option is A $\frac{3 h}{4}$
Center of mass of solid cone will always lies at distance $\frac{3 h}{4}$ from the tip of the cone.

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Distance of the centre of mass of a solid uniform cone from its vertex is z0. If the radius of its base is R and its height is h then z0 is equal to :

The correct option is A 3h4Center of mass of solid cone will always lies at distance 3h4 from the tip of the cone.

Distance of the centre of mass of a solid uniform cone from its vertex is $z_{0}$ . If the radius of its base is R and its height is h then $z_{0}$ is equal to :

The correct option is A $\frac{3 h}{4}$
Center of mass of solid cone will always lies at distance $\frac{3 h}{4}$ from the tip of the cone.