Distance travelled by a particle at any instant $t$ can be represented as $S = A (t + B) + C t^{2}$ . The dimensions of $B$ are

[M^{0} L^{0} T^{- 1}]

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[M^{0} L^{0} T^{1}]

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[M^{0} L^{1} T^{1}]

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[M^{0} L^{- 2} T^{1}]

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Solution

The correct option is B $[M^{0} L^{0} T^{1}]$
Given relation is $S = A (t + B) + C t^{2}$
Since, $B$ is added to time $t$ , so, it will have dimensions of time i.e. $[M^{0} L^{0} T^{1}]$

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Distance travelled by a particle at any instant t can be represented as S=A(t+B)+Ct2. The dimensions of B are

The correct option is B [M0L0T1]Given relation is S=A(t+B)+Ct2 Since, B is added to time t, so, it will have dimensions of time i.e. [M0L0T1]

Distance travelled by a particle at any instant $t$ can be represented as $S = A (t + B) + C t^{2}$ . The dimensions of $B$ are

The correct option is B $[M^{0} L^{0} T^{1}]$
Given relation is $S = A (t + B) + C t^{2}$
Since, $B$ is added to time $t$ , so, it will have dimensions of time i.e. $[M^{0} L^{0} T^{1}]$