wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Distilled water at 80C has hydronium ion (H3O+) concentration equal to 1×106mol/L.
The value of Kw at this temperature would be:

A
1×106
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1×109
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1×1014
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1×1012
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1×1012
The distilled water is neutral with equal concentrations of hydrogen ion and hydroxide ion. Whatever the temperature may be the water will always dissociate to give equal conc. of H+ ion and OH ion, that is it will always be neutral.
Hence, Kw=[H+][OH]
=1×106×1×106
=1×1012

flag
Suggest Corrections
thumbs-up
6
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon