Distinguish between the following pairs of compounds using the test given within brackets. Dilute sulphuric acid and dilute hydrochloric acid [using barium chloride solution].

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Solution

Sulphuric acid precipitates the insoluble sulphate of barium $(B a S O_{4})$ from the solution of barium chloride.

$B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + 2 H C l$

Dilute $H C l$ does not react with barium chloride solution, and thus, no precipitate is produced in the reaction.

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Basic Lead Carbonate

Standard XII Chemistry

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Distinguish between the following pairs of compounds using the test given within brackets. Dilute sulphuric acid and dilute hydrochloric acid [using barium chloride solution].

Sulphuric acid precipitates the insoluble sulphate of barium (BaSO4) from the solution of barium chloride. BaCl2+H2SO4→BaSO4+2HCl Dilute HCl does not react with barium chloride solution, and thus, no precipitate is produced in the reaction.

Sulphuric acid precipitates the insoluble sulphate of barium $(B a S O_{4})$ from the solution of barium chloride.

$B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + 2 H C l$

Dilute $H C l$ does not react with barium chloride solution, and thus, no precipitate is produced in the reaction.