Distinguish by adding: Sodium hydroxide solution and ammonium hydroxide solution to Calcium salt solution and lead salt solution

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Solution

Sodium hydroxide on reaction with calcium salt gives a milky white precipitate $C a (O H)_{2}$ which is sparingly soluble, while with lead salt solution it gives chalky white precipitate $P b (O H)_{2}$ which is soluble in excess of $N a O H$ .

$C a (N O_{3})_{2} + 2 N a O H \to C a (O H)_{2} ↓ + 2 N a N O_{3}$
(colourless) (milky white ppt.)

$P b (N O_{3})_{2} + 2 N a O H \to P b (O H)_{2} ↓ + 2 N a N O_{3}$
(colourless) (chalky white ppt.)

Ammonium hydroxide on reaction with lead salt gives chalky white precipitate $P b (O H)_{2}$ which is insoluble, but with calcium salts no precipitation occurs even in excess of $N H_{4} O H$ .

$P b (N O_{3})_{2} + 2 N H_{4} O H \to P b (O H)_{2} ↓ + 2 N H_{4} N O_{3}$
(colourless) (chalky white ppt.)

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Similar questions

Distinguish by adding : Sodium hydroxide solution and ammonium hydroxide solution to
(a) Calcium salt solution and lead salt solution.
(b) Lead salt solution and zinc salt solution.
(c) Copper salt solution and ferrous salt solution.
(d) Fe(II) salt solution and Fe(III) salt solution.
(e) Ferrous nitrate and lead nitrate

Q. Assertion :We can distinguish between

Z n^{2 +}

and

P b^{2 +}

using ammonium hydroxide solution. Reason: Zinc ions with ammonium hydroxide gives white precipitate of zinc hydroxide which dissolves in excess of ammonium hydroxide. Aqueous solution of lead salt do not show any change on treatment with ammonium hydroxide

Q. Distinguish by adding: Sodium hydroxide solution and ammonium hydroxide solution to
(b) Lead salt solution and zinc salt solution.

Distinguish by adding ammonium hydroxide solution to calcium salt and lead salt.

Distinguish by adding sodium hydroxide solution to calcium salt and lead salt.

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