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Q.24. Three charges - q, Q and - q are placed respectively at equal distances on a straight line. If the potential energy of the system of three charges is zero, then what is the ratio of Q : q?
(1) 1 : 1
(2) 1 : 2
(3) 1 : 3
(4) 1 : 4

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Solution

Dear student,
$T o t a l p o t e n t i a l e n e r g y o f s y s t e m = \frac{- q Q}{r} + \frac{- q Q}{r} + \frac{- q (- q)}{2 r} = 0 \frac{2 Q q}{r} = \frac{q^{2}}{2 r} Q = \frac{q}{4}$

Regards

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Solve this: Q.24. Three charges - q, Q and - q are placed respectively at equal distances on a straight line. If the potential energy of the system of three charges is zero, then what is the ratio of Q : q? (1) 1 : 1 (2) 1 : 2 (3) 1 : 3 (4) 1 : 4

Dear student, Total potential energy of system=-qQr+-qQr+-q-q2r=02Qqr=q22rQ=q4 Regards

Solve this:
Q.24. Three charges - q, Q and - q are placed respectively at equal distances on a straight line. If the potential energy of the system of three charges is zero, then what is the ratio of Q : q?
(1) 1 : 1
(2) 1 : 2
(3) 1 : 3
(4) 1 : 4

Dear student,
$T o t a l p o t e n t i a l e n e r g y o f s y s t e m = \frac{- q Q}{r} + \frac{- q Q}{r} + \frac{- q (- q)}{2 r} = 0 \frac{2 Q q}{r} = \frac{q^{2}}{2 r} Q = \frac{q}{4}$

Regards