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Question

Divergence of the vector field v(x,y,z)=(xcosxy+y)^i+(ycosxy)^j+[(sinz2)+x2+y2]^k

A
2zcosz2
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B
sinxy+2zcosz2
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C
xsinxycosz
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D
none of these
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Solution

The correct option is A 2zcosz2
Let V=V1^i+V2^j+V3^k then
divV=V1x+V2y+V3z
=x[xcosxy+y]+y[ycosxy]+=z[sinz2+x2+y2]
=2zcosz2

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