The correct option is C 192 According to problem 10 #160; #160; ÷2019 #160; = 10 ×1920 = #160; 192 ...

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Division of Fractions

Divide 10 b...

Question

Divide $10$ by $\frac{20}{19}$ .

\frac{19}{2}

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\frac{1}{20}

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\frac{19}{20}

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\frac{9}{2}

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Solution

The correct option is C $\frac{19}{2}$
According to problem
$10$ $\div \frac{20}{19}$

$= 10 \times \frac{19}{20}$
$= \frac{19}{2}$

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Similar questions

^{20} C_{0} +^{20} C_{1} + \dots +^{20} C_{8}

The remainder obtained when $(19^{103} + 19^{2})$ is divided by 20 is

\sum_{k = 0}^{10}^{20} C_{k} = 2^{19} + \frac{1}{2}

^{20} C_{10}

\frac{19}{20}

\frac{2}{20}

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