Question

Divide $1000$ into $2$ parts such that $10$% of one part equals $20$% of the other. Find the bigger part.

• A. $\frac{2000}{3}$
• B. $\frac{1000}{3}$
• C. $\frac{150}{3}$
• D. None of the above.

Answer 1

The correct option is A $\frac{2000}{3}$

Let $x$ be one part and $(1000-x)$ be the other part.

$10$% of $x$ = $20$% of $1000-x$ ....Given

$⟹\frac{10}{100}x=\frac{20}{100}(1000-x)$

$⟹x=2(1000-x)$

$⟹x=2000-2x$

$⟹3x=2000$

$x=\frac{2000}{3}$