Divide 15 into 2 parts such that the product of 2 numbers is 56.

- 7, - 8

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6, 9

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7, 8

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3, 12

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Solution

The correct option is D $7, 8$
Let one number = $x$
then the other number = $15 - x$
$(x) (15 - x) = 56$
$15 x - x^{2} - 56 = 0$
$x^{2} - 15 x + 56 = 0$
$(x - 7) (x - 8) = 0$
$x = 7, x = 8$

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