Divide 15y⁴ + 16y³ + $\frac{10}{3}$ y − 9y² − 6 by 3y − 2. Write down the coefficients of the terms in the quotient.

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Solution

$∴$ Quotient = 5y³ + (26/3)y² + (25/9)y + (80/27)
Remainder = ( $-$ 2/27)
Coefficient of y³ = 5
Coefficient of y² = (26/3)
Coefficient of y = (25/9)
Constant = (80/27)

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Similar questions

Divide $15 y^{4} + 16 y^{3} + \frac{10}{3} y - 9 y^{2} - 6$ by 3y - 2. Write down the co-efficients of the terms in the quotient.

(15 y^{4} - 16 y^{3} + 9 y^{2} - \frac{1}{3} y - \frac{50}{9})

(3 y - 2)

(15 y^{4} - 16 y^{3} + 9 y^{2} - \frac{1}{3} y - \frac{50}{9})

(3 y - 2)

5 y^{3} + 2 y^{2} - \frac{13}{3} y + \frac{25}{9}

(6 y^{5} + 15 y^{4} + 16 y^{3} + 4 y^{2} + 10 y - 35)

(3 y^{2} + 5)

Write the quotient and remainder when we divide.

$(15 x^{2} + x - 6)$ by $(3 x + 2)$

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