Question

Divide 184 into two parts such that one third of one part may exceed one seventh of another party by 8.

Answer 1

Let one part be x
other part = (184-x)

1/3rd of one part exceeds 1/7th of the other by 8. Thus
(1/3 × x) - [1/7 × (184-x)] = 8
⇒ x/3 - (184/7 - x/7) = 8
⇒ x/3 - 184/7 + x/7 = 8
⇒ x/3 + x/7 - 184/7 = 8
⇒ x/3 + x/7 = 8 + 184/7
⇒ (7x+3x)/21 = (56+184)/7
⇒ 10x/21 = 240/7
⇒ x = 240/7 × 21/10
⇒ x = 72

So one part = 72
other part = 184 - 72 = 112

Read more on Brainly.in - https://brainly.in/question/208511#readmoreLet one part be x
other part = (184-x)

1/3rd of one part exceeds 1/7th of the other by 8. Thus
(1/3 × x) - [1/7 × (184-x)] = 8
⇒ x/3 - (184/7 - x/7) = 8
⇒ x/3 - 184/7 + x/7 = 8
⇒ x/3 + x/7 - 184/7 = 8
⇒ x/3 + x/7 = 8 + 184/7
⇒ (7x+3x)/21 = (56+184)/7
⇒ 10x/21 = 240/7
⇒ x = 240/7 × 21/10
⇒ x = 72

So one part = 72
other part = 184 - 72 = 112