Divide $20$ into two parts such that one part is $8$ more than the other. What are the two parts.

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Solution

First part = x
Second part = x+8
According to question,
x+x+8= 20
2x = 12
x = 6

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Divide 20 into two parts such that one part is 8 more than the other. What are the two parts.

First part = xSecond part = x+8According to question,x+x+8= 202x = 12x = 6

Divide $20$ into two parts such that one part is $8$ more than the other. What are the two parts.

First part = x
Second part = x+8
According to question,
x+x+8= 20
2x = 12
x = 6