Divide - 20y -4y2-5y-3- 5y-4

The correct option is D 4(y^2+5y+3) 20(y+4)(y^2+5y+3)÷ 5(y+4) =2× 2× 5(y+4)×(y^2+5y+3)/5(y+4) =4(y^2+5y+3) ...

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Finding Square of a Number Using Identity

Divide : 20...

Question

Divide : $20 (y + 4) (y^{2} + 5 y + 3) \div 5 (y + 4)$

y^{2} + 5 y + 3

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4 (y^{2} - 5 y + 3)

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(y^{2} - 5 y + 3)

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4 (y^{2} + 5 y + 3)

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Solution

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Similar questions

20 (y + 4) (y^{2} + 5 y + 3) \div 5 (y + 4)

20 (y + 4) (y^{2} + 5 y + 3) \div 5 (y + 4)

20 (y + 4) (y^{2} + 5 y + 3) \div 5 (y + 4)

20 (y + 4) (y^{2} + 5 y + 3) \div 5 (y + 4)

Divide as directed.

(i) $5 (2 x + 1) (3 x + 5) \div (2 x + 1)$

(ii) $26 x y (x + 5) (y - 4) \div 13 x (y - 4)$

(iii) $52 p q r (p + q) (q + r) (r + p) \div 104 p q (q + r) (r + p)$

(iv) $20 (y + 4) (y^{2} + 5 y + 3) \div 5 (y + 4)$

(v) $x (x + 1) (x + 2) (x + 3) \div x (x + 1)$

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