Question

$Divide\left(24x{y}^2{z}^3\right)by\left(6y{z}^2\right).$

• A. $4x{y}^{2}z$
• B. $4x{y}^2{z}^2$
• C. $4xyz$
• D. $4x{y}^2$

Answer 1

The correct option is C $4xyz$

Given, the expression is
$24x{y}^2{z}^3÷6y{z}^2.$
$\text{Now,}24x{y}^2{z}^3\text{and}6y{z}^2$ can be written as,
$24x{y}^2{z}^3=2\times 2\times 2\times 3\times x\times y\times y\times z\times z\times z$
and
$6y{z}^2=2\times 3\times y\times z\times z$
Therefore,
$\frac{24x{y}^2{z}^3}{6y{z}^2}=\frac{2\times 2\times 2\times 3\times x\times y\times y\times z\times z\times z}{6\times y\times z\times z}$
After canceling the common terms, we get,
$\frac{24x{y}^2{z}^3}{6y{z}^2}=4\times x\times y\times z=4xyz$