Divide $2 a^{2} + 6 a b$ by $a + 3 b$ .

Open in App

Solution

If we divide $2 a^{2} + 6 a b$ by $a + 3 b$ then we've,
$\frac{2 a^{2} + 6 a b}{a + 3 b}$
$= \frac{2 a (a + 3 b)}{a + 3 b}$
$= 2 a$ .
So quotient is $2 a$ and remainder is $0$ .

Suggest Corrections

Similar questions

\sqrt{2 a^{2} + 2 \sqrt{6} a b + 3 b^{2}} =

\sqrt{2} a + \sqrt{3} b

Factorize:

$2 a^{2} + 2 \sqrt{6} a b + 3 b^{2}$

6 a^{4} - 2 a^{2} - a

a^{2}

2 a^{2} + 2 \sqrt{6} a b + 3 b^{2}

Divide (6 a b - b^{2} + 12 a c - 2 b c) by (b + 2 c)

Join BYJU'S Learning Program