Divide $2 x^{2} + 3 x + 1$ by $x + 2$

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Solution

$2 x^{2} + 3 x + 1 \div x + 2$
$2 x - 1$
$x + 2) 2 x^{2} + 3 x + 1$
$2 x^{2} + 4 x$
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$- x + 1$
$- x - 2$
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$3$

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