Divide :
${2 x}^{3} - {5 x}^{2} - 3 x b y (x - 1)$ ?

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Solution

$\begin{matrix} 2 x^{3} - 5 x^{2} - 3 x = x (2 x^{2} - 5 x - 3) = x (2 x^{2} - 6 x + x - 3) = x (2 x (x - 3) + 1 (x - 3)) = x (2 x + 1) (x - 3) \end{matrix}$
So,
$2 x^{3} - 5 x^{2} - 3 x$ by x-1 is ,
$\frac{x (2 x + 1) (x - 3)}{x - 1}$

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