Divide $(2 x^{3} + 7 x^{2} + 2 x - 3)$ by $(3 x - 1)$

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Solution

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$q (x) = \frac{2}{3} x^{2} + \frac{23}{9} x + \frac{41}{27}$
$r = \frac{41}{27} - 3 = \frac{41 - 81}{27} = \frac{- 40}{27}$

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