Divide-3 7 x3-28 x - 7 x

(7x3 + 28x ) nbsp; divide; 7x can be shown as: #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160;x2+47x #160; #1 ...

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Byju's Answer

Standard VIII

Mathematics

Division of a Monomial by Another Monomial

Divide:3 7 x3...

Question

Divide:

(3) (7x³ + 28x) ÷ 7x

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Solution

(7x³ + 28x ) ÷ 7x can be shown as:

$x^{2} + 4 7 x 7 x^{3} + 28 x - 7 x^{3} 0 + 28 x + 28 x - 0$

So, the quotient of the division is x² + 4 and the remainder is 0

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(35 x^{5} + 14 x^{3} - 28 x^{2}) \div (- 7 x)

Divide. Write the quotient and the remainder.
(a) $(21 x^{4} - 14 x^{2} + 7 x) \div 7 x^{3}$
(b) $(6 x^{5} - 4 x^{4} + 8 x^{3} + 2 x^{2}) \div 2 x^{2}$
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Simplify : $37 x - [5 x + {28 x - (19 x - 7 x)}]$

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Divide: (3) (7x3 + 28x) ÷ 7x

(7x3 + 28x ) ÷ 7x can be shown as: x2+47x 7x3+28x -7x3 0+28x +28x - 0 So, the quotient of the division is x2 + 4 and the remainder is 0

Divide:

(3) (7x³ + 28x) ÷ 7x

(7x³ + 28x ) ÷ 7x can be shown as:

$x^{2} + 4 7 x 7 x^{3} + 28 x - 7 x^{3} 0 + 28 x + 28 x - 0$

So, the quotient of the division is x² + 4 and the remainder is 0