Divide: $3 a^{3} - 9 a^{2} b - 6 a b^{2}$ by $- 3 a$

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Solution

given, $3 a^{3} - 9 a^{2} b - 6 a b^{2} \div - 3 a$

$= \frac{3 a^{3} - 9 a^{2} b - 6 a b^{2}}{- 3 a}$

$= \frac{- 3 a (- a^{2} + 3 a b + 2 b^{2})}{- 3 a}$

$= - a^{2} + 3 a b + 2 b^{2}$

$= 2 b^{2} + 3 a b - a^{2}$

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factorise;

1. (3a-2b)³+ (2b-5c)³+(5c-3a)³

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