Divide $3 m^{2} + 9 m + 6$ by m+2.

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Solution

$3 m^{2} + 9 m + 6 = 3 (m^{2} + 3 m + 2) = 3 (m^{2} + 2 m + m + 2) = 3 (m (m + 2) + (m + 2)) = 3 (m + 1) (m + 2)$
$(3 m^{2} + 9 m + 6) \div (m + 2) = \frac{3 m^{2} + 9 m + 6}{m + 2} = \frac{3 (m + 2) (m + 1)}{(m + 2)} = 3 (m + 1) = 3 m + 3$

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3 m^{2} + 9 m + 6

3 m^{2} + 9 m + 6

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On factorising $3 m^{2} + 9 m + 6$ , we get the factor(s) as:

Which of the following is/are the irreducible factor(s) of $3 m^{2} + 9 m + 6 ?$

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