wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Divide 30(a2bc+ab2c+abc2) by 6abc

Open in App
Solution

30(a2bc+ab2c+abc2)
=2×3×5[(a×a×b×c)+(a×b×b×c)+(a×b×c×c)]
=2×3×5×a×b×c(a+b+c)
Thus 30(a2bc+ab2c+abc2)÷6abc
=2×3×5×abc(a+b+c)2×3×abc
=5(a+b+c)
Alternatively 30(a2bc+ab2c+abc2)÷6abc
=30a2bc6abc+30ab2c6abc+30abc26abc
=5a+5b+5c
=5(a+b+c)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Division of Algebraic Expressions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon