Question

Divide $300$ into two parts so that half of one part may be less than the other by $48$.

• A. $143$ and $112$
• B. $148$ and $122$
• C. $168$ and $132$
• D. $163$ and $162$

Answer 1

The correct option is C $168$ and $132$

The two parts are $x$ and $300-x$.

$\frac{x}{2}=300-x+48\frac{3x}{2}=348x=116\left(2\right)=132$

Other part $=168$