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B
−6x2y−4y2+125+135x
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C
−6x2y+4y2−5+13
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D
−6x2y−4y2+116−12
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Solution
The correct option is B−6x2y+4y2−125+135x 30x3y2−20xy3+12xy−13y by −5xy 30x3y2−20xy3+12xy−13y−5xy=30x3y2−5xy−20xy3−5xy+12xy−5xy−13y−5xy =−6x2y+4y2−12/5+13/5x Answer (A) −6x2y+4y2−12/5+13/5x