Question

Divide $39$ into two parts such that their product is $324$.

Answer 1

Let first number be $x$

let the second number $39-x$

$\left(x\right)(39-x)=324$

$-x^2+39x-324=0$

$x^2-39x+324=0$

$x-27x+12x+324=0$

$x(x-27)-12(x-27)=0$

$x=12x=27$

$\therefore 12$ & $29$