Divide $3 x^{3} + 2 x^{2} + 13 x + 42$ by $(x + 2)$ and also verify the result.

Open in App

Solution

From the figure,
Quotient $= 3 x^{2} - 4 x + 21$
Remainder $= 0$

Verify;-
$x + 2 = 0$
$x = - 2$ , satisfy the given equation,

$3 x^{3} + 2 x^{2} + 13 x + 42$
$= 3 {(- 2)}^{3} + 2 {(- 2)}^{2} + 13 (- 2) + 42$
$= 3 (- 8) + 2 (4) + 13 (- 2) + 42$
$= - 24 + 8 - 26 + 42$
$= 0$

Therefore, $x = - 2$ satisfy the given equation.

Suggest Corrections

Similar questions

6 x^{2} - x - 15

(2 x + 3)

5 x^{5} + 4 x^{4} - 3 x^{3} + 2 x^{2} + 2

x^{2} - x

p (x) = 2 x^{4} - 3 x^{3} - 5 x^{2} + 8 x - 3

p (x)

(x - \frac{3}{2})

x^{2} + 3 x + 2

(x + 2)

Join BYJU'S Learning Program