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Question

Divide (3y+12b)(5ab)by (y+4b)(25a2b2)

A
35a+b
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B
53a+b
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C
=35ab
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D
=3a+5b
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Solution

The correct option is A 35a+b
The numerator can be written as 3(y+4b)(5ab)
and the denominator can be written as (y+4b)(5a+b)(5ab) [using identity a2b2=(a+b)(ab)
(3y+12b)(5ab)(y+4b)(25a2b2)=3(y+4b)(5ab)(y+4b)(5a+b)(5ab)
=35a+b

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(x + a)(x +b)= x^2 + x(a+ b) + ab
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