Divide $3 y^{3} + 2 y^{2} + y$ by $y$ .

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Solution

Given polynomial is $3 y^{3} + 2 y^{2} + y$ .
Dividing it by $y$ :
$(3 y^{3} + 2 y^{2} + y) \div y$
Taking $y$ common from all the terms of the given polynomial,
$\Rightarrow y (3 y^{2} + 2 y + 1) \times \frac{1}{y}$
$\Rightarrow 3 y^{2} + 2 y + 1$

Hence, $3 y^{3} + 2 y^{2} + y$ divided by $y$ is $3 y^{2} + 2 y + 1$ .

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