Divide 4a2bby 6ab2.
Division of monomials:
Quotient of two monomials = (Quotient of their numerical coefficients) (Quotient of their literal coefficients)
4a2bby6ab2=4×a2×b6×a×b2=2×a3×b=2a3b
Therefore, the result of division is 2a3b
Factorise:
a3−27b3+2a2b−6ab2
Multiply:
23ab by −14a2b