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Question

Divide 4a2bby 6ab2.


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Solution

Division of monomials:

Quotient of two monomials = (Quotient of their numerical coefficients) (Quotient of their literal coefficients)

4a2bby6ab2=4×a2×b6×a×b2=2×a3×b=2a3b

Therefore, the result of division is 2a3b


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