Divide 45 - 5 by the method of repeated subtraction-

By repeated subtraction, the number of times you subtract gives the answer 1. nbsp; 45 5 = 40 2. nbsp; 40 5 = 35 3. nbsp; 35 5 = 30 4. nbsp; 30 5 = 25 5 ...

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Byju's Answer

Standard VIII

Mathematics

Sum of the First n Odd Natural Numbers Is Equal to n Squared

Divide 45 ÷ 5...

Question

Divide 45 $\div$ 5 by the method of repeated subtraction.

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Solution

By repeated subtraction, the number of times you subtract gives the answer
1. 45-5 = 40
2. 40-5 = 35
3. 35-5 = 30
4. 30-5 = 25
5. 25-5 = 20
6. 20-5 = 15
7. 15-5 = 10
8. 10-5 = 5
9. 5-5 = 0
Therefore, 45 $\div$ 5 = 9

Suggest Corrections

Divide 45 ÷ 5 by the method of repeated subtraction.

By repeated subtraction, the number of times you subtract gives the answer 1. 45-5 = 40 2. 40-5 = 35 3. 35-5 = 30 4. 30-5 = 25 5. 25-5 = 20 6. 20-5 = 15 7. 15-5 = 10 8. 10-5 = 5 9. 5-5 = 0 Therefore, 45÷5 = 9

Divide 45 $\div$ 5 by the method of repeated subtraction.

By repeated subtraction, the number of times you subtract gives the answer
1. 45-5 = 40
2. 40-5 = 35
3. 35-5 = 30
4. 30-5 = 25
5. 25-5 = 20
6. 20-5 = 15
7. 15-5 = 10
8. 10-5 = 5
9. 5-5 = 0
Therefore, 45 $\div$ 5 = 9