Question

Divide $49x^{2}y{z}^2$ by $7y^2{z}^3$ .

• A. $\frac{7x}{yz}$
• B. $\frac{7x^2}{yz}$
• C. $\frac{7x^3}{yz}$
• D. $\frac{7x^2}{y^{2}z}$

Answer 1

The correct option is B $\frac{7x^2}{yz}$

Given, the expression is $\frac{49x^{2}y{z}^2}{7y^2{z}^3}$ .

We write $49x^{2}y{z}^2$ and $7y^2{z}^3$ in irreducible factor forms as,
$49x^{2}y{z}^2=7\times 7\times x\times x\times y\times z\times z7y^2{z}^3=7\times y\times y\times z\times z\times z$

$\therefore \frac{49x^{2}y{z}^2}{7y^2{z}^3}=\frac{7\times 7\times x\times x\times y\times z\times z}{7\times y\times y\times z\times z\times z}$

$=\frac{7\times x\times x}{y\times z}$
$=\frac{7x^2}{yz}$