Divide $4 p^{2} + 2 p + 2$ by $^{'} 2 p^{'}$ .

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Solution

Given polynomial $4 P^{2} + 2 P + 2$ divided by $2 p$
$4 p^{2} + 2 p + 2 \div 2 p$
$\Rightarrow 4 p^{2} + 2 p + 2 \times \frac{1}{2 p}$
$\Rightarrow 2 (2 p^{2} + p + 1) \times \frac{1}{2 p}$
$\Rightarrow \frac{2 p^{2} + p + 1}{p}$

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