Divide $4 x^{3} + 12 x^{2} + 11 x + 3 b y x + 1$ and then find the quotient.

$2 x^{2} + 3 x + 3$

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$4 x^{2} + 6 x + 1$

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$4 x^{2} + 8 x + 3$

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$8 x^{2} + 11 x + 3$

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Solution

The correct option is C
$4 x^{2} + 8 x + 3$

$\begin{matrix} 4 x^{2} + 8 x + 3 x + 1 & 4 x^{3} + 12 x^{2} + 11 x + 3 - 4 x^{3} - 4 x^{2} 8 x^{2} + 11 x + 3 - 8 x^{2} - 3 x 3 x + 3 - 3 x - 3 0 \end{matrix}$

Quotient = 4 $x^{2}$ + 8x + 3

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