Divide: $- 4 x^{3} - 6 x^{2} + 8 x$ by $2 x$

(- 2 x^{2} - 3 x + 4)

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2 x (2 x^{2} - 3 x + 4)

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(- 2 x^{2} - 3 x + 4)

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x (- 2 x^{2} - 3 x - 4)

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Solution

The correct option is B $(- 2 x^{2} - 3 x + 4)$
Quotient
= $\frac{- 4 x^{3} - 6 x^{2} + 8 x}{2 x} = - \frac{4 x^{3}}{2 x} - \frac{6 x^{2}}{2 x} + \frac{8 x}{2 x}$
= $- 2 x^{2} - 3 x + 4$

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(3 x + 2 x^{2} + 4 x^{3}) \div (x - 4)

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- 2 x^{2} + 3 x - 4 = 0

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