Divide $4 x^{4} - 3 x^{3} - 2 x^{2} + 6 x - 7$ by $x - 2$ .

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Solution

On Dividing $4 x^{4} - 3 x^{3} - 2 x^{2} + 6 x - 7$ by $x - 2$

putting $x - 2 = 0 \Rightarrow x = 2$

We get,
Remainder $= 4 * 2^{4} - {3.2}^{3} - {2.2}^{2} + 6.2 - 7 = 37$

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