Question

Divide:
5$pq(p^2-q^2)÷2p(p+q)$

Answer 1

$p^2-q^2=(p-q)(p+q)$

$\left(5pq\right(p^2-q^2\left)\right)÷\left(2p\right(p+q\left)\right)=\frac{5pq(p^2-q^2)}{2p(p+q)}=\frac{5pq(p-q)(p+q)}{2p(p+q)}=\frac{5}{2}q(p-q)$