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Question

Divide 6x3y2z2 by 3x2yz.

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Solution

6x3y2z23x2yz=6×x×x×x×y×y×z×z3×x×x×y×z = 2x(3-2)y(2-1)z(2-1)=2xyz

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Division of an Expression by a Monomial
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