Divide $60 a^{2} b y 12 a^{2}$ .

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Solution

Division of monomials.
Quotient of two monomials $=$ (Quotient of their numerical coefficients) (Quotient of their literal coefficients)
$\begin{array}{rcl} 60 a^{2} b y 12 a^{2} & = & \frac{60 \times a^{2}}{12 \times a^{2}} \\ = & 5 \times 1 \\ = & 5 \end{array}$
Therefore, the result of divison is $5$ .

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