Divide: $(6 a^{5} + 8 a^{4} + 8 a^{3} + 2 a^{2} + 26 a + 35)$ by $(2 a^{2} + 3 a + 5)$
Answer: $3 a^{3} - 3 a^{2} + a + 7$

True

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False

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Solution

The correct option is B False
$2 a^{2} + 3 a + 5$ $¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯) 6 a^{5} + 8 a^{4} + 8 a^{3} + 2 a^{2} + 26 a + 35 ($ $3 a^{3} - \frac{1}{2} a^{2} - \frac{11}{4} a$
$- (6 a^{5} + 9 a^{4} + 15 a^{3})$
$¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ - a^{4} - 7 a^{3} + 2 a^{2}$
$- (- a^{4} - \frac{3}{2} a^{3} - \frac{5}{2} a^{2})$
$¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ \frac{- 11}{2} a^{3} + \frac{9}{2} a^{2} + 26 a$
$- (\frac{- 11}{2} a^{3} + p (a)$
$¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ r (a)$ where, $r (a)$ is remainder.

As, the answer doesn't match, so, FALSE.

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Similar questions

(6 a^{5} + 3 a^{4} + 8 a^{3} + 2 a^{2} + 26 a + 35)

(2 a^{2} + 3 a + 5)

\frac{a^{2} - 16}{a^{3} - 8} \times \frac{2 a^{2} - 3 a - 2}{2 a^{2} + 9 a + 4} \div \frac{3 a^{2} - 11 a - 4}{a^{2} + 2 a + 4}

[3 a^{2} - 2 a^{2} + 9 a^{2} - {6 a^{2} - (- 2 a^{2} + 3 a^{2})}]

- [3 a^{2} - 2 a^{2} + 9 a^{2} - {6 a^{2} - (- 2 a^{2} + 3 a^{2})}]

A^{3} + 2 A^{2} + 5 A + I = 0, then A^{- 1}

- (3 A^{2} + 2 A + 5)

3 A^{2} + 2 A + 5

3 A^{2} - 2 A - 5

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