Divide: $6 x^{3} y^{2} z^{2}$ by $3 x^{2} y z$

Open in App

Solution

To factorize : $6 x^{3} y^{2} z^{2}$ by $3 x^{2} y z$
$= \frac{6 x^{3} y^{2} z^{2}}{3 x^{2} y z} = 2 x y z$

Suggest Corrections

Similar questions

Divide:

$6 x^{3} y^{2} z^{2}$ by $3 x^{2} y z$

Divide :~

1. $6 x^{3} y^{2} z^{2} b y 3 x^{2} y z$

2. $15 m^{2} n^{3} b y 5 m^{2} n^{2}$

3. $24 a^{3} b^{3} b y - 8 a b$

4. $- 21 a b c^{2} b y 7 a b c$

5. $72 x y z^{2} b y - 9 a^{2} b^{2} c^{3}$

- x y^{2} z^{2} + 2 y z^{2} x + 3 x^{2} y z - 7

- 6 x^{2} y z

$(- 5 x y) \times (- 3 x^{2} y z)$

- x y^{2} z^{2} - 2 y z x^{2} + 3 x^{2} y z - 7

- 6 x^{2} y z

6 x^{3} y^{3} z^{3} - 12 x^{4} y^{2} z^{2} + 42 x^{2} y z

Join BYJU'S Learning Program