Divide $6 x^{4} - 8 x^{3} + 12 x - 4$ by $2 x^{2}$

$3 x^{2} - 4 x - \frac{2}{x^{2}}$

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$3 x^{2} - 4 x + \frac{6}{x} - \frac{2}{x^{2}}$

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$3 x^{2} - 4 x + \frac{6}{5 x} - \frac{2}{x^{2}}$

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$3 x^{2} - 4 x + \frac{6}{x} - \frac{1}{x^{2}}$

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Solution

The correct option is B
$3 x^{2} - 4 x + \frac{6}{x} - \frac{2}{x^{2}}$

Step 1: If you are dividing by a monomial, you can split the problem into pieces by putting each term in the numerator over the denominator.

$\frac{6 x^{4}}{2 x^{2}} - \frac{8 x^{3}}{2 x^{2}} + \frac{12 x - 4}{2 x^{2}}$

Step 2: Simplify each term. Use the rules for exponents to simplify the variables in each term and reduce the fractions.

$3 x^{2} - 4 x + \frac{6}{x} - \frac{2}{x^{2}}$

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Similar questions

If 6x⁴+8x³-5x²+ax+b is completely divisible by polynomial 2x²-5 then find the value of a and b

(6 x^{5} - 4 x^{4} + 8 x^{3} + 2 x^{3}) \div 2 x^{2}

(6 x^{4} + 8 x^{3} + 17 x^{2} + 21 x + 7)

(3 x^{2} + 4 x + 1)

6 x^{4} + 8 x^{3} + 17 x^{2} + 21 x + 7

3 x^{2} + 4 x + 1

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